Dr. Dommer is interested in testing whether the gender breakdown in his introductory biology class is...

please like ??

The following information is provided: The sample size is N = 45, the number of favorable cases is X = 20, and the sample proportion is p= * = 20 = 0.4444, and the significance level is a = = 0.05 (1) Null and Alternative Hypotheses The following null and alternative hypotheses need to be tested: Ho:p=0.60 Ha: p = 0.60 This corresponds to a two-tailed test, for which a z-test for one population proportion needs to be used. (2) Rejection Region Based on the information provided, the significance level is a = 0.05, and the critical value for a two-tailed test is ze = = 1.96. The rejection region for this two-tailed test is R= {z : [2] > 1.96} (3) Test Statistics The z-statistic is computed as follows: 2 = P – po V po(1 – po)/n 0.4444 – 0.60 (0.60(1 – 0.60)/45 = -2.13 (4) Decision about the null hypothesis 2.13 > Zc = 1.96, it is then concluded that the null Since it is observed that |z| hypothesis is rejected. Using the P-value approach: The p-value is p = 0.0332, and since p= 0.0332 < 0.05, it is concluded that the null hypothesis is rejected. (5) Conclusion It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that the population proportion p is different than po, at the a = 0.05 significance level.