## Question

###### Question 14 2pc A generator coil is rotated through 15 revolutions in 280 ms. calculate the...

Question 14 2pc A generator coil is rotated through 15 revolutions in 280 ms. calculate the maximum em that is generated if the coil is circular with a 12 cm diameter has a turns, and is in a uniform 1.85 T magnetic field. 2300 V 9000 V 3607 7207 NO 1400V

Question 13 2 pts Calculate the magnetic field density in a 25 turn copper coil with radius 7.2 cm if the coil is rotated 90° in the field from full flux to zero flux in a time of 45 msec resulting in an average current of 18 mA. The coil has as total resistance of 0.085 2. O 1.7E-4T 2.7E-3T 3.8E-5 T 0 4.6E-3T 5.8E-5T

Question 12 2 pts Calculate the current needed in a 1150 loop peni cular coil (solenoid) 0.880 m in radius to create a 1.20 T field (typicalota MRSumentar its center. 830 A 2200 A 3500 A 1100 A 4400 A

Calculate the net magnetic force (size and direction) on the rectangular loop due to the current in the straight wire. The current in the straight wire is a constant4.5 A and the current in the loop is a constant 6.8 A. (The image is the similar to problem #Unit 22 notes.) 5.00 126 5. NAxtract 2.9E-SN Recal MO 2.86 7 N. Reper 2.8E-7 Natal B.WEEN WERON

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14) NA W = 15x20 = 336.599 rad 280XT3 sec D=12cm, N=320 B=1.855 (max. = NBAW = 320x1.85%A8(0.12)3336.599 e maxo = 2253.65 v rouded off (max=2008 option @ is correct 13 ) At N=25, R=7.2cm, at= 45 msec, I = 18 mA Ro=0.0850 emf (e) = A = N.AR? AB - N. ARE B ₂ e = 25XXX (7.2x12? ² x B 45X13 - B = 1,69x604 T = 1-7X164) option (a) is correct = 18 X10 XO-OSSN =n= 1150 =lo I, 12 x 4 Xto Mo 2 x 4X2 24 4 Cm 12) B=1:20 T R=0.880m B = MONI = 40 x12' x 11 50x I = 1:20 > I = 830.37A) option (a) is correct And 13# for this Question data is not visible. I1 = 4.5A, Iz-6.8A, That Fab F 2743 778 2x10x4.5468x4 1 1FAB B A I3cm. sem 25 X 8 Xt tay - ابيا 8 Free 51x10 N attractive.

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