Question
An evaporative cooling tower removes 1 x 106 Btu/hr of heat from the cooling water from...
An evaporative cooling tower removes 1 x 106 Btu/hr of heat from the cooling water from a condenser of a steam power plant. The temperature of the water is reduced from 120 °F to 110 °F. Air enters the cooling tower at 91 °F and 60% relative humidity and air leaves at 100 °F and 82% relative humidity. The quantity of make-up water is:
Answers
solens Warm water cold Il mim From steamtable =) at T3=1200 F & ha= [email protected] T3 [email protected]=78.02 boty Que's Greinen! Ti=910F T2=100° F 0,= 0.6 02=0.82 Air out T2,02 T3=120° F Airin TE91°F TA=110 F 0, 0.6 From Psychrometrić chart > Ti=91°F " 0,50.6 hor= 42.5 beta/lb of dry ain V. - 41% of die Wi=0.0188 lb Mastura/lb of dia. T2=100f & 02=0.82 ha=57 betuleb of d.o. &= 14.77 ft3/lb of dia. W₂ = 0.03 lb Moistury/lb of da Ta=110° F at 88 lety The Sinces Qurumond - mis (hz-ha) lob belcher = mig (88–78.02) miza 10/B600 letu/min 9.98 miza 1670 letu/min# Mass of make up maten mima mizmit mima mz-ma= Loss of water in ais mim= mis-ma= (W2-Wi) na # Emungy balance for cooling towar => ma, hit misha= mazhat maha mach, hz) & mighs = (miz - (Wa-wi) ima) ha mis (ha-ha)= mia (ha-hi) - (W2_W,) maha 1670x ( 88-78.02) nia (37-42-5) - (0.03 -0.018) max 7s. na = 1228.75 lle/min so Make up water flow rates mm= (W2-W,) na m'm= (0.03-0.018)x1228.75 mima 14.74 lle/min
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