Question
In the same circuit as shown in the previous page, the switch is now closed. Calculate...
In the same circuit as shown in the previous page, the switch is now closed. Calculate the following quantities A (oV) a) Equivalent capacitance Ceq b) Total charge Qror stored in Ceq. c) Potential at the point B. (Assume that the point A has OV.) d) Charge Qi which is stored in the capacitor Ci. e) Charge q which goes through the switch (from point B to C) just after it is closed.
Answers
C_1 = 6 mu F, C_2 = 3 mu F, E = 6v C_3 = 3 mu F, C_4 = 6 mu F a) c_1 and c_3 are in parallel. Replace them by c_1 + c_3 c_2 and c_4 are in parallel. Replace them by c_2 + c_4 c_1 + c_3 and c_2 + c_4 are in series. C_eq = (c_1 + c_3) (c_2 + c_4)/(c_1 + c_3) + (c_2 + c_4) = (9) (9)/9 + 9 = 4.5 mu F b) Q_tot = c_eq E = (4.5) (6) (10^-6) = 27 mu c c) points B and c are same potential. The potential difference across the entire combination is equal to E = 6v. This is divided as E = 6v = V_13 + v_24 \r\n since c_1 + c_3 and c_2 + c_4 are in series (c_1 + c_3)v_13 = (c_2 + c_4)v_24 = > v_13 = v_24 v_13 = v_24 = E/2 = 3v. Hence potential at point b
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