Question
*15-4. Each of the cables can sustain a maximum tension of 5000 lb. If the uniform...

*15-4. Each of the cables can sustain a maximum tension of 5000 lb. If the uniform beam has a weight of 5000 lb, determine the shortest time possible to lift the beam with a speed of 10 ft/s starting from rest. 4 ft 311
Answers
Ans. Given data! P free body diagram sooo lb OP Aft st В. X 24h 4 3 st 3 508olb T T 0 + p Efr=0; The tension in both cables is same, since beam is symmetrically banged. P-at sino =0 P-(2x500x40 p = 8000 lb ② Impulse momentum principle tz +Pmvit ES fudt = my = 185.24 Slugs 9 32.2 t; = 1064 13. :.Vi0 FtLS -- 155.2460) + S 8000t -Soooodt =155.27(10) 8000 (+ 509)- 5000 (t-o) = 155217 8000lt-0)-5000 ft-0) = 1555257 F = 0.51755 Shortest time to ti గ000 W co see m = r 2 v2 = t t o lift the beam.
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