Question
(8%) Problem 11: A student launches a small rocket which starts from rest at ground level....

(8%) Problem 11: A student launches a small rocket which starts from rest at ground level. At a height of h- 1.85 km the rocket reaches a speed of ve 395 m/s. At that height the rocket runs out of fuel, so there is no longer any thrust propelling it. Take the positive direction to be upward in this problem. Ctheespertta.com 33% Part (a) Assuming constant acceleration, what is the rocket's acceleration, in meters per second squared, during the period from its launch until it runs out of fuel? Correct a-42.17 33% Part (b) After the rocket's engine turns off at a height of h- 1.85 km, it continues to move upward due to the velocity that it reached. What is the rocket's acceleration, in meters per second squared, during the period from engine shutoff until it returns to the ground? Ignore air resistance. a 9.80 Correct a--9.8 33% Part (c) Calculate the maximum height, in meters above ground level, that the rocket reaches. Grade Sammary Deductions Potential hmax6945 15% 85%
Answers
As the rocket has reached a height of 1.85km = 1850m before it's engine turns off. We will calculate the distance travelled after engine is turned off and add it to 1850m
distance travelled after engine is turned off =
therefore, total height reached = 1850+7960.5
= 9.8 Km
S=2XS 02-3952 x (-9.8) = 7960.5m 2
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