## Question

###### Lab+5+Conservation+of+Energy (1) Microsoft Word Acrobat Title Subtitle Subtle En 1 Normal 1 No Spacing Heading 1...

## Answers

Let us consider a spring having a spring constant k N/m

2)Here the Work done by the spring can be determined from the graph by finding the area under the graph

That is Work done =1/2*b*h= 1/2*0.04*3.3=0.066 J

3)The average force can be calculated using the equation F=-kx

where k is the spring constant, x is the strecth = 1cm =0.01m

Work done = 1/2 k x

^{2}= 0.066 JTherefore k= (0.066/0.0001)*0.5= 330 N/m

Force F= kx= 330* 0.01= 3.3N

4)Work done in each segment is given by W= 1/2 kx

^{2}

^{W1=}1/2 k x^{2}= 1/2*330*0.01 =0.0165JW2=1/2 * 330*0.02

^{2}=0.066JW3=1/2 * 330*0.03

^{2}=0.1485JW4=1/2 * 330*0.04

^{2}=0.264JW5=1/2 * 330*0.05

^{2}=0.4125JFor comparing these values with the obtained values in the post lab question2 ,take the difference between the two 5),Work done by a spring= F.dx

F= 5.4- 2.3x

^{2}+4.3 x^{3}.W=5.4- 2.3x

^{2}+4.3 x^{3}dx ; x=0.05m5.4x-2.3x

^{3}/3+4.3 x^{4}/4 =0.26904 J1) Graph to calculate the workdone by a spring.

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