Question
Lab+5+Conservation+of+Energy (1) Microsoft Word Acrobat Title Subtitle Subtle En 1 Normal 1 No Spacing Heading 1...


Answers
Let us consider a spring having a spring constant k N/m
2)Here the Work done by the spring can be determined from the graph by finding the area under the graph
That is Work done =1/2*b*h= 1/2*0.04*3.3=0.066 J
3)The average force can be calculated using the equation F=-kx
where k is the spring constant, x is the strecth = 1cm =0.01m
Work done = 1/2 k x2 = 0.066 J
Therefore k= (0.066/0.0001)*0.5= 330 N/m
Force F= kx= 330* 0.01= 3.3N
4)Work done in each segment is given by W= 1/2 kx2
W1= 1/2 k x2 = 1/2*330*0.01 =0.0165J
W2=1/2 * 330*0.022=0.066J
W3=1/2 * 330*0.032=0.1485J
W4=1/2 * 330*0.042=0.264J
W5=1/2 * 330*0.052=0.4125J
For comparing these values with the obtained values in the post lab question2 ,take the difference between the two 5),Work done by a spring=
F.dx
F= 5.4- 2.3x2 +4.3 x3.
W=
5.4- 2.3x2 +4.3 x3 dx ; x=0.05m
5.4x-2.3x3/3+4.3 x4/4 =0.26904 J
1) Graph to calculate the workdone by a spring.
We were unable to transcribe this imageWe were unable to transcribe this image1 unit χ aus s o.oim. FoRcE l unit alona yaxs 3 2 an Are undea the bagh o.o66 Nm