Question
An object with a mass of #8 kg# is lying still on a surface and is compressing a horizontal spring by #5/4 m#. If the spring's constant is #3 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?
An object with a mass of #8 kg# is lying still on a surface and is compressing a horizontal spring by #5/4 m#. If the spring's constant is #3 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?
Answers
The static coefficient must equal 0.048
Explanation:
We are looking at a case of balanced forces here. The force of the spring
#F=kx# will push on the mass with a force of
#F = (3(kg)/s^2)(5/4m)# =#15/4# NStatic friction will be equal in magnitude to this, as there is no motion.
Writing the force of friction as
#F_f=muF_N = mumg#
#15/4N = mu (8kg)(9.8m/s^2)#
#3.75 N = muxx78.4N#
#mu=3.75/78.4 = 0.048#
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