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What ion will result if a piece of magnesium metal is placed in #CuSO_4(aq)# solution?

Question

What ion will result if a piece of magnesium metal is placed in #CuSO_4(aq)# solution?
What ion will result if a piece of magnesium metal is placed in #CuSO_4(aq)# solution?

Answers

Why #Mg^(2+)#....

Explanation:

Magnesium, an alkaline earth metal, is a MUCH more active metal than copper... And we can appreciate this by the standard redox potentials...

#Mg^(2+) + 2e^(-) rarr Mg# #;E^@=-2.732*V#

#Cu^(2+) + 2e^(-) rarr Cu# #;E^@=+0.337*V#

And thus copper ion will deposit on the magnesium surface, and the magnesium electrode will corrode completely.....


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