## Question

###### (c) Acylindrical specimen of stainless steel having a diameter of 12.8 mm and a gauge length...

(c) Acylindrical specimen of stainless steel having a diameter of 12.8 mm and a gauge length of 50.800 mm is pulled in tension. The data acquired was used to plot engineering stress versus engineering strain as shown in the following two graphs (please note that fig. b is a blown-up clastic portion of (a)). Use the o-curves to complete parts through (vi) Stress (MP) 0.00 0.02 0.04 0.06 0.08 0.10 Strain Fig (a). - curve of stainless steel Stress (MPa) -- - - - - - 200 -- 0 000 0002 0.004 0.006 0008 Strain Fig. (b) a plot of os curve for a blown up elastic portion of fig. (a) here above

ii. Determine the yield strength at a strain offset of 0.002. coul d d bonunda rolled about tid iii. Determine the tensile strength of this alloy. tobulin 2012 iv. What is the approximate ductility, in percent elongation? yugou dogabb bramborola de V. Compute the modulus of resilience.

## Answers

sonly W ☺ ☺ have - been asked. 800F GOK Stress (MPa) 200 0.000 0.002 0.004 0.006 0.008 Strain -A line with slope of young's Modulus is drawn at 0.002 strain value as shown in figure (dotted line). - This dotted line intersect the true stress vs True straindiagram. Curve at Point Y marked in the - Project a horizontal line from point A on Y-axis to get the value of yield strength at Strain offset 0.002 (Yellow line shows Projection) 90.002 = 750 MPa g offset (11) The Ultimate maximum attained Tensile strength of tensile stress is the value of stress in uniaxial tensilethe failure of test the before specimen. 1500 1250 Stress (MP) 500 0.00 0.02 00041 008 0.10 0.06 Strain → Maximum Stress point is Projected on Yoaxis to get Tensile strength of Material (Yellow line) Sut=1250 MPa♡. Initial length (Co) = 50.8 mm Stress (MPa) 50 0.00 0.02 0.04 0.08 010 0.06 Strain 0.10 (0.12 0.115 We are finding Maximum value of engineering strain attained before failure of specimen. - For this we have marked Point M and projected it on X-axis using Yellow line. -→ The value of final strain is Ef=oolis # = engineering strain change in length orignal length Lo ef=al % Elongation = 2*100 -- % Elongations Ep X 100 % 1 % Elongation = 11.5 (me as wre of ductility)The modulus of resilience is maximum energy (Ur )that can be absorbed per unit volume without creating a permanent distortion (within the elastic limit). It can be calculated by integrating the stress-strain curve from zero to the elastic limit. Stress (MP) Elastic limit SON Leo 0.00 0.00 0.04 0.06 0.08 0.10 0.05 Strain Elastic Point strain at = 0.05 Stress at = 750MPa Elastic Point. Modulus of Resilience - Sc. Es = 4(750)(0.05) | 18.75 MPa

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