(c) Acylindrical specimen of stainless steel having a diameter of 12.8 mm and a gauge length...

sonly W ☺ ☺ have - been asked. 800F GOK Stress (MPa) 200 0.000 0.002 0.004 0.006 0.008 Strain -A line with slope of young's Modulus is drawn at 0.002 strain value as shown in figure (dotted line). - This dotted line intersect the true stress vs True strain

diagram. Curve at Point Y marked in the - Project a horizontal line from point A on Y-axis to get the value of yield strength at Strain offset 0.002 (Yellow line shows Projection) 90.002 = 750 MPa g offset (11) The Ultimate maximum attained Tensile strength of tensile stress is the value of stress in uniaxial tensile

the failure of test the before specimen. 1500 1250 Stress (MP) 500 0.00 0.02 00041 008 0.10 0.06 Strain → Maximum Stress point is Projected on Yoaxis to get Tensile strength of Material (Yellow line) Sut=1250 MPa

♡. Initial length (Co) = 50.8 mm Stress (MPa) 50 0.00 0.02 0.04 0.08 010 0.06 Strain 0.10 (0.12 0.115 We are finding Maximum value of engineering strain attained before failure of specimen. - For this we have marked Point M and projected it on X-axis using Yellow line. -

→ The value of final strain is Ef=oolis # = engineering strain change in length orignal length Lo ef=al % Elongation = 2*100 -- % Elongations Ep X 100 % 1 % Elongation = 11.5 (me as wre of ductility)

The modulus of resilience is maximum energy (Ur )that can be absorbed per unit volume without creating a permanent distortion (within the elastic limit). It can be calculated by integrating the stress-strain curve from zero to the elastic limit. Stress (MP) Elastic limit SON Leo 0.00 0.00 0.04 0.06 0.08 0.10 0.05 Strain Elastic Point strain at = 0.05 Stress at = 750MPa Elastic Point

. Modulus of Resilience - Sc. Es = 4(750)(0.05) | 18.75 MPa