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Determine the mass (g) of aluminum deposited in an electrolytic cell using a current of 0.750...

Question

Determine the mass (g) of aluminum deposited in an electrolytic cell using a current of 0.750...

Determine the mass (g) of aluminum deposited in an electrolytic cell using a current of 0.750 A for 1.2 hour (1 hour = 3,600
Determine the mass (g) of aluminum deposited in an electrolytic cell using a current of 0.750 A for 1.2 hour (1 hour = 3,600 s) A13+ (aq) + 3e - Al(s) O 0.000839 g 0 2.20 g 0 0.3029 O 0.906 g O 0.625 g

Answers

0.75A for 1.2 homs. Supplies (0.75*1-2x3000) Condant change. - 3240 Coulomb If АЛ +3 > AL so 3x 965000 contomt change can dep


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