Question
Given: - 4.0% by mass of ammonium chloride - 1.75kg of the solution An aqueous solution...
given:
- 4.0% by mass of ammonium chloride
- 1.75kg of the solution

An aqueous solution is to be prepared that will be 4.0% by mass ammonium Chloride. What mass of ammonium Chloride AND what mass of water will be needed to prepare 1.7516 (kilograms of this Solution?
Answers
SOLUTION:
For a Binary solution(a solution containing two components),
% of Mass =(Mass of solute /Mass of solvent) *100
Here ,
NH4Cl is solute & water is solvent .
Simply 4% by mass means the solution contains 4% NH4Cl of its total mass .Rest will be the mass of water.
Now ,
Given mass of solution =1.75 kg
Then , Mass of NH4Cl = 4% of 1.75 kg
= (1.75*4)/100
=0.07 kg
Now ,Mass of water required =1.75 _ 0.07
=1.68 kg
So, Mass of NH4Cl required =0.07 kg
Mass of water required =1.68 kg
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