Question
(1 point) The heights of a ball (in feet) at time t (in seconds) is given...
(1 point) The heights of a ball (in feet) at time t (in seconds) is given by the formula s(t) = 64 - 16(t - 1)2. Consider the following average rate of change expression. AV = $(1) – 8(0.5) 1 -0.5 (a) Compute the value of AV: (b) What are the units on AV? A. feet per second squared B. meters per second C. meters D. feet per second E. seconds F. meters per second squared G. feet (c) What does this value measure geometrically? A. Height: The increase in the height of the ball from t= 0.5 tot=1. B. Distance: The distance between the points (0.5, 0.5)) and (1,8(1)). c. Slope: The slope of the line between the points (0.5, 8(0.5)) and (1, 8(1)).
Answers
1-0.5 94-0-64+ 166-05 Guven formula s(t) = 64-16 (t-1)- Ar= S(1) – 8(0.5) - 64 - 16 (1-12 - [64-16 (0-5-4 1-05 - 1-0.5 eht 16 (-0.5) 1680 5 x 80 Oh I Our 8.0 =8 (2) Value of AV =18 (6 units of AV = D. feet per second c) This value measure geometrictly & Blope : The slope of the line between the pointy / (0.5, 5(0:55)) and (4, 3(4)) -
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