Question
9. A certain 4th row element has the following ionization energies: 12 = 1310 kJ/mol I3...
9. A certain 4th row element has the following ionization energies: 12 = 1310 kJ/mol I3 = 2652 kJ/mol 14 = 4175 kJ/mol Is = 9581 kJ/mol 16 = 11533 kJ/mol Now tell me, most peerless predictor of periodic properties, what is the identity of the element? Please provide an explanation as well.
Answers
I2 = 1310KJ/mole I3 = 2652KJ/mole I4 = 4175KJ/mole , I5 = 9581KJ/mole I6 = 11533KJ/mole
The large gap between I4 and I5 . The element valence shell contains four electrons.
The element is Ge
Germanium >>>>answer
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