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# 14.0 g of acetylsalicylic acid were obtained from 23.9 g of salicylic acid. Determine the percentage...

## Question

###### 14.0 g of acetylsalicylic acid were obtained from 23.9 g of salicylic acid. Determine the percentage...

14.0 g of acetylsalicylic acid were obtained from 23.9 g of salicylic acid.

Determine the percentage yield of acetylsalicylic acid.

What I did: 23.9 g ÷ 138 g = 0.1732 mol

Known Information:

Reactant mass: 23.9 g

Product mass: 14.0 g

Reactant moles: 0.1732 moles

acetylsalicylic acid C₉H₈O₄ (12•9) + (1•8) + (4•16) = 180 g/mol

Would it be 14.0 g ÷ 180 g? Please explain.

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