Question
Rewrite the net ionic reaction. If there is NO reaction, simply write NR. 1) (Pb(NO3)2 +...
Rewrite the net ionic reaction. If there is NO reaction, simply write NR.
1) (Pb(NO3)2 + Na3PO4)
2) (CuSO4 + Pb(NO3)2)
3) (AlCl3 + Pb(NO3)2)
4) (Zn(C2H3O2)2 + Pb(NO3)2)
5) (CuSO4 + Zn(C2H3O2)2)
6) (AlCl3 + Zn(C2H3O2)2)
7) (CuSO4 + AlCl3)
Answers
- 3Pb(NO3)2 (aq) + 2Na3PO4 (aq) → Pb3(PO4)2 (s)+ 6NaNO3 (aq)
Net ionic reaction : 3Pb2+(aq) + 2(PO4)3-(aq) → Pb3(PO4)2(s)
- CuSO4 (aq)+ Pb(NO3)2 (aq) → Cu(NO3)2 (aq) + PbSO4 (s)
Net ionic reaction : Pb2+ (aq) + (SO4)2-(aq) → PbSO4 (s)
- 2AlCl3 (aq) + 3Pb(NO3)2 (aq) → 2Al(NO3)3 (aq) + 3PbCl2 (s)
Net ionic reaction : 3Pb2+ (aq) + 6Cl- (aq) → 3PbCl2 (s)
- Zn(C2H3O2)2 (aq) + Pb(NO3)2 (aq) → NR
- CuSO4 (aq) + Zn(C2H3O2)2 (aq) → NR
- 2AlCl3 (aq) + 3Zn(C2H3O2)2 (aq) → 2Al(C2H3O2)2 (s) + 3ZnCl2 (aq)
Net ionic reaction : 2Al3+ (aq) + 2 C2H3O2- (aq) → 2Al(C2H3O2)2 (s)
- 3CuSO4 (aq) + 2AlCl3 (aq) → NR
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