Problem 2: A residential air-conditioner with an actual cooling capacity of 14.06 kJ/s (4 tons), cools and dehumidifies a steady stream of air flowing over the cooling coil. Actual states for the Ref...

Problem 2: A residential air-conditioner with an actual cooling capacity of 14.06 kJ/s (4 tons), cools and dehumidifies a steady stream of air flowing over the cooling coil. Actual states for the Refrigerant 134a are given Notice that the compressor efficiency is less than 100% and there are small pressure drops given for the heat exchangers. The coefficient of performance is 3.51 for the actual cycle. Changes in kinetic and potential energy are negligible. The warm indoor air temperature entering the unit is at 50% relative humidity and 30 C. The chilled air exits the unit at 5 "C at 100% relative humidity. Atmospheric pressure is 101 kPa. 34a properties Actual States (kJ/kg) (°C) (kPa) (m3/kg) 0.0163 a) Evaporator inlet0.264337.6 b) Evaporator exit c) Condenser inlet sh 60.0 1200 0.01835 d) Condenser exit 106.19 0 292.8 0.0689 247.23 287.44 106.19 0.0 40.0 1016 0.00087 A.) Find the Refrigerant R-134a mass flowrate and compressor isentropic efficiency, 10 pts kg/s,c-row B.) Find the amount of condensate per unit mass of dry air, and find the dry air mass flowrate, kg/kg-DA, m water / m dry air ) airl - dry airkg-DA/s Air-Conditioned Space Outdoor Environment m Cold air Text = 5°C *-100 % a 37°C Cold Coil Q14.06 kJ/s R-134a m Warm air Tin -30 °O ф-50 % MR134a- ? M water liquid In condensate @5 °C