Question
The maximum amount of manganese(II) sulfide that will dissolve in a 0.186 M potassium sulfide solution...
The maximum amount of manganese(II) sulfide that will dissolve in a 0.186 M potassium sulfide solution is ___ M.
- The Ksp for manganese(II) sulfide is
| 5.1 × 10-15 |
Answers
K2S here is Strong electrolyte
It will dissociate completely to give [S2-] = 0.186 M
At equilibrium:
MgS <----> Mg2+ + S2-
s 0.186 + s
Ksp = [Mg2+][S2-]
5.1*10^-15=(s)*(0.186+ s)
Since Ksp is small, s can be ignored as compared to 0.186
Above expression thus becomes:
5.1*10^-15=(s)*(0.186)
5.1*10^-15= (s) * 0.186
s = 2.742*10^-14 M
Answer: 2.7*10^-14 M
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