## Question

###### Problem 15.79 20 of 36 Review Constants Periodic Table For the equilibrium 21B7(9) = 1:(9) +...

Problem 15.79 20 of 36 Review Constants Periodic Table For the equilibrium 21B7(9) = 1:(9) + Bre(9) K = 8.5 x 10- at 150°C. Part A if 2.9x10- atm of IBr is placed in a 2.0-L container, what is the partial pressure of IBr after equilibrium is reached? Express your answer to two significant figures and include the appropriate units. 0.0104 atm Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining

## Answers

Ans- given Reaction is 21B8 (g) Ź Iz (g) + B82(g) Kp = 8.5x10 3 initial pressure of IB8=2.9x102 atm Now, 2 I BJ 19 Ž Iz (g) + B82 (9) initial 2.9x102 - ofter 2.9x10-2-2x x x so, Kp = 1. 0 (0) 12.98102-220)2 = [] (foz] [PIBO] (8.5x103) (2.9%10*2 27723 x? 0.9662? +.0009862–71.485 X107-0 We get a= 0.00225742 so, equillibrium pressude of 'I BY' is given by = .029 - 2x0.00225742 = 0.02448516 so, final pressuse is E 0.0245 atm

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