Question
Part 1- Could someone tell me which of these are soluble and insoluable. Part 2- How...
Part 1- Could someone tell me which of these are soluble and insoluable.
Part 2- How do you write a net ionic equation for the precipitate?
Briefly review the reagents involved in the procedures for test tubes #2 and 3 (see pp. 8-3 and 8-4 in your lab manual.). Each test tube started with a solution containing the sodium or potassium salt of each anion. In test tube 2, a solution of silver nitrate (AgNO3) was added. In test tube 3, a solution of barium chloride (Bach) was added. In both cases, we willinore the addition of nitric acid.) Refer to the solubility guidelines from the GKFBD textbook (pp. 170-171), and determine which anion compounds will form a precipitate upon the addition of silver nitrate (test tube 2) and barium chloride (test tube 3). In the table below, mark an 'X' in each box that corresponds to the formation of precipitate. [if you have your anion table from the lab with you, you can look at that as well; but you should use the solubility guidelines to determine which precipitates will form.) AgNO3 Balla AgNO3 Balla Anion Test Test Anion Test Test Compound Tube 2 Tube 3 Compound Tube 2 Tube 3 NaCH3COO Nal NazC03 NaNO3 NaF NaSCN NaCl Na2SO4 NaBr Na3PO4 2. For each precipitate formed above, write the appropriate net ionic equation. Phase labels and ion charges are required to receive full credit. First, write the reactions for test tube #2, then the reactions for test tube #3. Please show ONLY the net ionic equations here, use a separate sheet of scratch paper to work out the molecular and overall ionic equations if you wish. TEST TUBE 2 REACTIONS
Answers
Anion Compound Test tube 2 (AgNO3) Test tube 3 (BaCl2) Overall molecular equation Net ionic equation NaCH3COO CH3COOAg (soluble)
(CH3COO)2Ba (soluble)
NaCH3COO + AgNO3 = NaNO3 + CH3COOAg
2 NaCH3COO + BaCl2 = 2 NaCl + (CH3COO)2Ba
CH3COO- (aq) + Ag+ (aq) = CH3COOAg (s)
2 CH3COO- (aq) + Ba2+ (aq) = (CH3COO)2Ba (s)
Na2CO3 Ag2CO3 (insoluble) BaCO3 (insoluble) Na2CO3 + 2AgNO3 = 2 NaNO3 + Ag2CO3
Na2CO3 + BaCl2 = 2 NaCl + BaCO3
2Ag+ (aq) + CO32- (aq) = Ag2CO3 (s)
Ba2+ (aq) + CO32-(aq) = BaCO3 (s)
NaF AgF
(soluble)
BaF2 (insoluble) NaF + AgNO3 = NaNO3 + AgF
2NaF + BaCl2 = 2NaCl + BaF2
Ag+(aq) + F- (aq) = AgF (s)
Ba2+ (aq) + 2F- (aq) = BaF2 (s)
NaCl AgCl
(insoluble)
No precipitate NaCl + AgNO3 = NaNO3 + AgCl
2NaCl + BaCl2 = No reaction
Ag+(aq) + Cl- (aq) = AgCl (s)
NaBr AgBr (insoluble) BaBr2
(soluble)
NaBr + AgNO3 = NaNO3 + AgBr
2 NaBr + BaCl2 = 2 NaCl + BaBr2
Ag+(aq) + Br- (aq) = AgBr (s)
Ba2+ (aq) + 2Br- (aq) = BaBr2 (s)
NaI AgI
(insoluble)
BaI2
(soluble)
NaI + AgNO3 = NaNO3 + AgI
2 NaI + BaCl2 = 2 NaCl + BaI2
Ag+(aq) + I- (aq) = AgI (s)
Ba2+ (aq) + 2 I- (aq) = BaI2 (s)
NaNO3 No precipitate Ba(NO3)2 (soluble) NaNO3 + AgNO3 = No reaction
2 NaNO3 + BaCl2 = 2 NaCl + Ba(NO3)2
Ba2+ (aq) + 2NO3- (aq) = Ba(NO3)2 (s)
NaSCN AgSCN (insoluble) BaSCN (soluble) NaSCN + AgNO3 = NaNO3 + AgSCN
2 NaSCN + BaCl2 = 2 NaCl + BaSCN
Ag+ (aq) + SCN- (aq) = AgSCN (s)
Ba2+ (aq) + 2 SCN- (aq) = BaSCN (s)
Na2SO4 Ag2SO4 (insoluble) BaSO4 (insoluble) Na2SO4 + 2AgNO3 = 2NaNO3 + Ag2SO4
Na2SO4 + BaCl2 = 2 NaCl + BaSO4
2Ag+(aq) + SO42- (aq) = Ag2SO4 (s)
Ba2+(aq) + SO42- (aq) = BaSO4 (s)
Na3PO4 Ag3PO4
(insoluble)
Ba3(PO4)2 (insoluble) Na3PO4 + 3AgNO3 = 3NaNO3 + Ag3PO4
2Na3PO4 + 3BaCl2 = 6 NaCl + 2Ba3(PO4)2
3Ag+ (aq) + PO43- (aq) = Ag3PO4 (s)
3Ba2+ (aq) + PO43- (aq) = 2Ba3(PO4)2 (s)
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