The graph below shows the voltage across a 27 μF capacitor vs. time. Find the current...

Here we are having voltage wave form let us find out first the equation of voltage t elementof (0, 9) = By straight line equation we will find voltage equation y - y_1 = y_2 - y_1/x_2 - x_1 (x - x_1) (V - 0) = -50 - 0/9 - 0 (t - 0) V = -50/9 t \r\n Same as previous one we will calculate for 9 < t < 14 V = 16t - 194 for 14 < t < 19 V = -6t + 11H V = {-50/9 t 0 < t lessthanorequalto 9 16t - 194 9 < t lessthanorequalto 14 -6t + 114 14 < t lessthanorequalto 19 let find dv/dt dv/dt = {-50/9 0 < t lessthanorequalto 9 16 9 < t lessthanorequalto 14 -6 14 lessthanorequalto t < 19 \r\n as we know i_c = C dv/dt so here C = 27 mu f i_C (mu f) = {-150 0 < t