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12 8) (10 pts) Inspired by donuts, I decided to make a clock. The I0 9...

Question

12 8) (10 pts) Inspired by donuts, I decided to make a clock. The I0 9...

12 8) (10 pts) Inspired by donuts, I decided to make a clock. The I0 9 2 3 pendulum for the clock is made of a donut (R-5.0 cm, M- 0.5 kg. eom-7.5x10 kg m2) attached to the end of a stick (L- 20 cm, m 0kg). Will my clock run on-time, fast, or slow? Support your answer with calculations. (note: assume the 20 cm length of stick is from the center af the donut to 765 9) (8 pts) An object oscillates in the manner described by (2.0m)e쁘-Gs)) If the amplitude of the oscillation is 10m at time t#20s, find the damping constant of the oscillator. a) b) In the space below sketch a graph of the oscillations for 6.0s.
12 8) (10 pts) Inspired by donuts, I decided to make a clock. The I0 9 2 3 pendulum for the clock is made of a donut (R-5.0 cm, M- 0.5 kg. eom-7.5x10 kg m2) attached to the end of a stick (L- 20 cm, m 0kg). Will my clock run on-time, fast, or slow? Support your answer with calculations. (note: assume the 20 cm length of stick is from the center af the donut to 765 9) (8 pts) An object oscillates in the manner described by "(2.0m)e쁘-Gs)) If the amplitude of the oscillation is 10m at time t#20s, find the damping constant of the oscillator. a) b) In the space below sketch a graph of the oscillations for 6.0s.

Answers

(8) My clock will be running fast.

According to given picture, it shows that the pendulum for my clock is made of donut which attached to the end of a stick. In this picture, i think that pendulum looks running fast.

Using a formula, we have

T = 2\pi\sqrt{}L / g

where, L = length of a stick = 0.2 m

g = acceleration due to gravity = 9.8 m/s2

then, we get

T = (6.28 rad) \sqrt{}[(0.2 m) / (9.8 m/s2)]

T = (6.28 rad) \sqrt{}0.0204081 s2

T = [(6.28 rad) (0.1428 sec)]

T = 0.896 sec

(9) An expression for damped simple harmonic motion which will be given below as -

x (t) = A e-bt/2m cos (omegat + phi)

An object oscillates in the manner which is described by -

x = (2 m) e-bt/(6kg) cos { [(2\pi/3) s-1] t }

a. If the amplitude of an oscillation is 1 m at time t = 2 sec, then the damping constant of an oscillator will be given by -

(1 m) = (2 m) e-bt/(6kg) cos { [(2\pi/3) s-1] (2 s) }

[(1 m) / (2 m)] = e-bt/(6kg) cos (4.186 rad)

ln (0.5) = - [b t / (6 kg)] (0.9973)

- [(0.6931) (6 kg)] = - b [(2 s) (0.9973)]

b = [(4.1586 kg) / (1.99465 s)]

b = 2.08 kg/s


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