Question
The puck in the figure has a mass of 0.17 kg. Its original distance from the...
The puck in the figure has a mass of 0.17 kg. Its original distance from the center of rota- tion is 41.2 cm, and the puck is moving with a speed of 67.5 cm/s. The string is pulled downward 11.8 cm through the hole in the frictionless table.
What is the magnitude of the work was done on the puck? Treat the hockey puck as a point mass. Answer in units of J.
Answers
Given mass of puck is m = 0.17 kg
r1 = 41.2 cm = 0.412 m, v1 = 67.5 cm/s = 0.675 m/s
r2 = 41.2-11.8 cm = 29.4 cm = 0.29 m
we know that angular momentum is constant
by conservation of angular momentum
L1 = L2
m v1r1 = m v2r2
V2 = v1r1/r2
= 0.675*0.412/0.29
= 0.959 m/snow change in k.e = 0.5*m(v2^2 - v1^2)
= 0.5*0.17(0.959^2 -0.675^2) J
which is equal to work done on puck to pull it to a distance of 11.8 cm down
from work energy theorem , work done = change in k.e