10. A student heats 100 mL of water to 76 °C. The temperature of the surrounding...

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Given that,

Initial temperature of water,

Final temperature of water,

Temperature of surroundings,

Time interval,

Applying Newton's law of cooling:

Again,Given that,

Initial temperature of water,

Final temperature of water,

Applying Newton's law of cooling:

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Ti = 76°C

T, = 34"

T. = 26C

t=25 min

T =7; – k (T + F – z)

76 - 34 76 +34 -- 26 25 min =K

42 = 29K

42 ..K= 725

Ti = 34°C

T = 24°C

T =7; – k (T + F – z)

- - ( 2 - 26)

10 42 t=725 X 3

10 x 725 ...t= 42 x 3 min

iit= 57.54 min