Question
A particle with a charge of 4.43 x 10^-6C is placed between two parallel plates and feels a force of -4.71 x 10^-4N. What is the strength of the field between the two plates?
A particle with a charge of 4.43 x 10^-6C is placed between two parallel plates and feels a force of -4.71 x 10^-4N. What is the strength of the field between the two plates?
Answers
#-1.06xx10^2"N/C"# Explanation:
Field strength is defined as the force per unit charge acting at a point in the field. The expression is:
#E=F/q#
#:.E=(-4.71xx10^(-4))/(4.43xx10^(-6))#
#:.E=-1.06xx10^2"N/C"#
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