## Question

###### Assignment Gradebook Chapter 13, Section 13.2, Problem 07 According to the records of the National Safety...

## Answers

Answer is:

Yes.Well we need to perform a chi square test of goodness of fit in order to answer this question:

(1)

Null and Alternative HypothesesThe following null and alternative hypotheses need to be tested:

Ha: Some of the population proportions differ from the values stated in the null hypothesis

This corresponds to a Chi-Square test for Goodness of Fit.

(2)

Rejection RegionBased on the information provided, the significance level is α=0.01, the number of degrees of freedom is df=6−1=5, so then the rejection region for this test is R={χ2:χ2>15.086}.

(3)

Test StatisticsThe Chi-Squared statistic is computed as follows:

(4)

Decision about the null hypothesisSince it is observed that χ2=37.061>χc2=15.086, it is then concluded that

the null hypothesis is rejected.(5)

ConclusionIt is concluded that the null hypothesis Ho is

rejected.Therefore, there is enough evidence to claim that some of the population proportions differ from those stated in the null hypothesis, at the α=0.01 significance level.

Please let me know in comments in case anything is unclear. Will reply ASAP. Do upvote if satisfied!Yes, these data show a significantly different distribution of accidental deaths as compared to that for the entire United StatesThe following table is obtained (fo-fe)2fe (438-428.72)1428.72-0.201 (110-139.8)2/139.8 6.352 (69-37.28)2137.28 26.989 (26-37.28)2137.28 3.413 (77-74.56)2174.56 0.08 (212-214.36)-/214.36 0.026 Categories Motor Vehicles Falls Drowning Burns Poison Other Observed 438 110 69 26 Expected 932 0.46-428.72 932 0.15-139.8 932 0.04-37.28 932 0.04-37.28 932 0.08-74.56 932 0.23-214.36 212 932 932 37.061 Sum -Ho : PI = 0.16.P2 0. 15.P3 = 0.04.24 0.04.75 = 0.08. P6 = 0.230.2016.352 26.989 + 3.413+0.08+0.026 37.061