Question
Use the interactive Punnet Squares Level 2 to answer the following questions. Suppose the parents indicated...
Answers
1.
Answer :- 39
Explanation :-
Dihybrid Ratio of cross between Yellow color,green color, Round seed and wrinkled seed - 9:3:3:1
cross between - YyRr × YyRr produces :-
Yellow Round seed = 9/16
Green Round seed = 3/16
Yellow wrinkled seed = 3/16
Green wrinkled seed = 1/16
In this way , if total pea is 208 ,number of yellow and wrinkled offspring will be 39.
2.
Answer is :- 25 %
Explanation :-
If one of pea plant is homozygous recessive for both genes and it results in cross Yy Rr × yy rr, then the percentage of yellow and wrinkled offspring will be 25%.
3.
Answer is :- 6 yellow, round : 2 yellow, wrinkled : 6 green, round : 2 green, wrinkled
Explanation :-
one of the pea plants is homozygous recessive for seed color, resulting in the cross Yy Rr × yy Rr.
6 yellow, round : 2 yellow, wrinkled : 6 green, round : 2 green, wrinkled , represents the ratio of phenotypes of the offspring.
(A) is wrong answer because it has written 9 yellow, round: 3 yellow, wrinkled: 3 green, round: 1 green, wrinkled.
(B) is wrong answer because it has written 4 yellow, round: 4 yellow, wrinkled : 4 green, round : 4 green, wrinkled.
(C) is wrong answer because it has written 6 yellow, round: 6 yellow, wrinkled: 2 green, round: 2 green, wrinkled.
1.
Answer :- 39
Explanation :-
Dihybrid Ratio of cross between Yellow color,green color, Round seed and wrinkled seed - 9:3:3:1
cross between - YyRr × YyRr produces :-
Yellow Round seed = 9/16
Green Round seed = 3/16
Yellow wrinkled seed = 3/16
Green wrinkled seed = 1/16
In this way , if total pea is 208 ,number of yellow and wrinkled offspring will be 39.
2.
Answer is :- 25 %
Explanation :-
If one of pea plant is homozygous recessive for both genes and it results in cross Yy Rr × yy rr, then the percentage of yellow and wrinkled offspring will be 25%.
3.
Answer is :- 6 yellow, round : 2 yellow, wrinkled : 6 green, round : 2 green, wrinkled
Explanation :-
one of the pea plants is homozygous recessive for seed color, resulting in the cross Yy Rr × yy Rr.
6 yellow, round : 2 yellow, wrinkled : 6 green, round : 2 green, wrinkled , represents the ratio of phenotypes of the offspring.
(A) is wrong answer because it has written 9 yellow, round: 3 yellow, wrinkled: 3 green, round: 1 green, wrinkled.
(B) is wrong answer because it has written 4 yellow, round: 4 yellow, wrinkled : 4 green, round : 4 green, wrinkled.
(C) is wrong answer because it has written 6 yellow, round: 6 yellow, wrinkled: 2 green, round: 2 green, wrinkled.
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