## Question

###### The heat of vaporization of alcohol is 879 #Jg^-1#. What is the energy (in J) required to vaporize #4.50# #g# of alcohol, #C_2H_5OH#?

The heat of vaporization of alcohol is 879 #Jg^-1#. What is the energy (in J) required to vaporize #4.50# #g# of alcohol, #C_2H_5OH#?

## Answers

#879# joules per gram times#4.50# grams equals#3955.5# joules## Explanation:

This is a fairly straightforward question. Each gram of alcohol requires

#879# #J# to vaporise it, and there are#4.5# #g# , so we simply multiply.Notice the units:

#Jg^-1*g = J#

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