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Part c calculate the freezing/boiling point for 18.0 g of decane, C10H22, in 50.0 g CHCl3...

Question

Part c calculate the freezing/boiling point for 18.0 g of decane, C10H22, in 50.0 g CHCl3...
part c
calculate the freezing/boiling point for 18.0 g of decane, C10H22, in 50.0 g CHCl3
part e
calculate the freezing/boiling point for 0.48 mol ethylene glycol and 0.18 mol KBr in 166g H2O

Carbon w orden


TABLE 13.3 · Molal Boiling-Point-Elevation and Freezing-Point-Depression Constants Normal Boiling Normal Freezing Solvent Poi
Carbon w orden
TABLE 13.3 · Molal Boiling-Point-Elevation and Freezing-Point-Depression Constants Normal Boiling Normal Freezing Solvent Point ("C) K. (°C/m) Point (°C) K(°C/m) Water, H2O 100.0 0.51 0.0 1.86 Benzene, CH 80.1 2.53 5.5 Ethanol, C H OH 78.4 1.22 -114.6 1.99 Carbon tetrachloride, CCI 76.8 -22.3 29.8 Chloroform, CHCI 61.2 3.63 -63.5 4.68 5.12 5.02

Answers


partc per te mass of decane = 18.09 lecane 18 = 0.1268 142 molality = moles 0.127 mass of solvent 0.050 = 2.535 m от; -ку хт


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