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Mirrors and Lenses O O O O Concave mirror Convex mirror Plane mirror Converging lens Diverging...
Mirrors and Lenses O O O O Concave mirror Convex mirror Plane mirror Converging lens Diverging lens Focal length (cm): Object distance, x (cm): Object height (cm): Image distance, x' (cm): Image height (cm): 40.0 200.0 50.0 50.0 -12.5 Concept Questions Notes Audio Intro Oo ©
Question 6 Concept Simulation 25.2 illustrates the concepts pertinent to this problem. A 2.10-cm-high object is situated 13.4 cm in front of a concave mirror that has a radius of curvature of 12.1 cm. Calculate (a) the location and (b) the height of the image. (a) Number Units (b) Number Units Click if you would like to Show Work for this question: Open Show Work
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Sawtion Size of object , n, = 2.10 cm u, Object distance = 13.4 cm Radius of curvenure ,R = 12.1cm a) Let location of object be a For mirrors R= 2B 8- = b = 6.05 cm using mirron's formula 1 * * * 8 ma For 6=-6.05cm concave mirror teste u=-13.4cm ♡ - * - to 1 -1 10 (-6.05) (-13.4) ? = -13.4 +6.05 6.05x13.4 L = 6.05 x 13.4 . -13.4+6.05 6 - 8107 - - 11.03 cm -7.356) As magnification 1 m = = h where he is size of Image mario e o m = -11:03 -13.4 6) As magnification m=- = n₂ the where he is size of Image TC-11.03 ) +13.4 2.10 hz = -11:03x2.10 13.4 h₂ =-1.728 h₂=-1.73 cm smage is - ve that Inverted sign shoves
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