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How do you solve #-4j + 14= - 2( 2j - 7)#?

Question

How do you solve #-4j + 14= - 2( 2j - 7)#?
How do you solve #-4j + 14= - 2( 2j - 7)#?

Answers

#j=0#

Explanation:

This requires a lot of moving around and negative knowledge.

#-4j+14=-2(2j-7)#

First, we must expand the brackets:

#-2(2j-7) = -4j^2+14#

Then we can move on to changing the numbers around (remember to change the signs:

#-4j+14=-4j^2+14#

#-4j+4j^2=-14+14#

And then simplify from there:

#j=0#

Hope this helped.


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