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A pair of constant forces of magnitude F = 14.3 N is applied to opposite sides...

Question

A pair of constant forces of magnitude F = 14.3 N is applied to opposite sides...

A pair of constant forces of magnitude F 14.3 N is applied to opposite sides of the axle of a top, as shown in the figure. Th

A pair of constant forces of magnitude F = 14.3 N is applied to opposite sides of the axle of a top, as shown in the figure. The diameter of the axle is d = 7.95 mm. The angle θ, which has a value of 37.7°, describes the steepness of the top\'s sloping sides. The moment of inertia of the top about its spin axis is I = 0.579 kg·m2. What is the tangential acceleration at of the point labeled P, which is at a height of h = 6.27 cm above the floor?

A pair of constant forces of magnitude F 14.3 N is applied to opposite sides of the axle of a top, as shown in the figure. The diameter of the axle is d 7.95 mm. The angle 8, which has a value of 37.7, describes the steepness of the top's sloping sides. The moment of inertia of the top about its spin axis is0.579 kg m2 What is the tangential acceleration at of the point labeled P, which is at a height of h 6.27 cm above the floor? Number em/s Your answer is off by an integer numerical factor. When calculating the torque due to the applied forces, did you use the given axle diameter or its radius? R P frictionless floor

Answers

F- 14.3N Torque about axes Ratahom Caxesơfaxe Fol-C4:3) (7.95%!») -f.dh t fd..ニ Momunt ๙.


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