How do you solve #7/112=(c-3)/8#?

See the entire solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(8)# to eliminate one fraction while keeping the equation balanced:

#color(red)(8) xx 7/112 = color(red)(8) xx (c - 3)/8#

#56/112 = cancel(color(red)(8)) xx (c - 3)/color(red)(cancel(color(black)(8)))#

#1/2 = c - 3#

Now, add #color(red)(3)# to each side of the equation to solve for #c# while keeping the equation balanced:

#1/2 + color(red)(3) = c - 3 + color(red)(3)#

#1/2 + 6/2 = c - 0#

#7/2 = c#

#c = 7/2#