Question
What is the magnitude of the reaction force on the beam at E?
Drawing not toscale. The beam weighs 100 N. Neglect the thickness of the beam. Assume the beam has a uniform cross section and density, and assume that points A, B, and E havethe same y coordinate.
A) What is the magnitude of the reaction force on the beam at E? (N)
B) What is the direction of the reaction force on the beam at E? (° CCW from X axis)
C) What is the magnitude of the reaction force on the beam at A? (N)
D) What is the direction of the reaction force on the beam at A? (° CCW from X axis)
Answers
net torque about beam A is zero.
400*sin60*1.9+100*2.85+780*0.8=760*(1.9+1.4)+N_ver*1.9*3.
so that N_ver=-165(N).
----------------
it is downward.
-----------------
so that N_verA=100+400*sin60+165-760=-150(N). (down)
N_horA=400*cos60+780=980(N) (to the left).
so N=990(N).
angle. alpha=189 (degrees)
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