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How do you simplify #root4(42)/root4(7)#?

Question

How do you simplify #root4(42)/root4(7)#?
How do you simplify #root4(42)/root4(7)#?

Answers

#root n (a)/root n (b)=root n(a/b)#

Explanation:

This goes for any #n#, as long as they're equal (of course):

#=root 4 (42/7)=root 4 6#


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