Question
Part A - The activity of a certain isotope dropped from 3200 Ci to 800 Ci...
Part A - The activity of a certain isotope dropped from 3200 Ci to 800 Ci in 4.0 years. What is the half-life of this isotope (in years)? Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining Submit Request Answer Part B - How many half lives have elasped in a sample with a half life of 3 hours after 24 hours? Calculate the number of half lives that elapse after 24 hours if a sample has a half life of 3 hours. Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining
Answers
A)
After n half lives,
N/No = (1/2)^n
put values:
800/3200 = (1/2)^n
(1/4) = (1/2)^n
(1/2)^2 = (1/2)^n
n = 2
So, 2 half lives is 4.0 years.
So, half life = 2.0 years
Answer: 2.0 years
B)
Total time = 24 hours
Half life = 3 hours
Use:
Number of half lives = total time / half life
= 24/3
= 8
Answer: 8
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