## Question

###### 500 N 4 = 0.30 -0.25 Determine whether the block shown is in equilibrium and find...

500 N 4 = 0.30 -0.25 Determine whether the block shown is in equilibrium and find the magnitude and direction of the friction force when P-400 N. 2001

500 N U=0,30 41 = 0.25 20°/

## Answers

500 N Ms 0.30 р K = 0.25 20° P = 400 N N psino f. B.D. of Blockin P Pos20° 50081220 20 500 GS 20° 20 500 fs N = P s'n 20% + 500 GS 20° 400 sin20 + 500 6520° 606.65 N force along the slope F = P Cos20 500 sinzoo 400 Cos20 500 fin20° 204.87 N (towards upward] since net force is along upward the slope. friction force will down word. Max. static = M N act So, (fstatican friction force 0.3 X 606.65 181-995 N. max. since , F> (fstotie ) may So block will Start moving upward and the friction force acting is kinetic friction force in downward direction. on the blockfriction force = lk N Hence, 0-25 X 686.65 M 151-6625 f 151.66 N in downward direction of slope. "

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