Show all work EvaluateG(x, y) dx,G(x, y) dy, and G(x, y) ds on the indicated curve...

Integrals_c G (x, y) dx = integrals^pi/4_0 2 (5 cos t) (5 sin t). (- 5 sin t) = -250 integrals^pi/4_0 sin^2 t middot cos t dt. Put sin t = u implies cos t dt = dt limits t 0 pi /4 u 0 1/ squareroot 2. Implies integrals_c G (x, y) dx = (- 250) integrals^1/squareroot 2_c u^2 du = (- 250) . [4^3/3]^1/squareroot 2_0 = -250/3. 1/(squareroot 3)^3 = -250/3. 1/2 squareroot 2 implies integrals_c G (x, y) dx = -125/3 squareroot 3 \r\n (2) integrals_c G (x, y) dy = integrals^pi/4_0 2 (5 cos t) (5 sin t) (5 cos t) dt = 250 integrals^pi/4_0 cos^2 t middot sin t dt put cos t = u implies - sin t dt = du implies sin t dt = -du. Limits. T 0 pi/4 u 1 1 squareroot 2 implies integrals_c G (x, y) dy \r\n .