Question
How do you evaluate the definite integral by the limit definition given #int xdx# from [-2,3]?
Answers
Definite integral
#int_(-2)^3xdx=5/2# Explanation:
A definite integral is an integral with upper and lower limits. The definite integral of
#f(x)# is a number and it represents the area under the curve#f(x)# from#x=a# to#x=b# .Its value is equal to
#F(b)-F(a)# , where#F(x)=intf(x)dx# and this is expressed as#int_a^bf(x)dx=[F(x)]_a^b# As
#intxdx=x^2/2+c#
#int_(-2)^3xdx=[x^2/2+c]_(-2)^3# =
#[(3)^2/2+c-((-2)^2/2+c)]# =
#[9/2+c-4/2-c]# =
#5/2# Observe that constant term
#c# has cancelled out. As such we can avoid adding#c# to#F(x)# , while calculating definite integral.Further see the following figure depicting area under the curve
#f(x)=x# considered above.![]()
Observe that area under the
#x# -axis (shown as pink in colour) has been taken as negative. If in some application of this concept, this is to be taken as positive, one must take adequate care.