Question
How do you factor #64x^3-8#?
How do you factor #64x^3-8#?
Answers
#8(2x-1)(4x^2+2x+1)# Explanation:
Factor
#64x^3-8# First factor out the GCF
#8# .
#8(8x^3-1)# Rewrite the expression as a difference of cubes, where
#a=2x# and#b=1# .
#8((2x)^3-1^3)# Use the difference of cubes to answer this question:
#a^3-b^3=(a-b)(a^2+ab+b^2)#
#8((2x)^3-1^3)=8(2x-1)((2x^2+(2x*1)+1^2)=#
#8(2x-1)(4x^2+2x+1)=#
#8(2x-1)(4x^2+2x+1)#
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