Question
How do you factor #12x^2-39x+9#?
How do you factor #12x^2-39x+9#?
Answers
We can play with factors of 12 (1x12, 2x6, 3,4) and factors of 9 (1x9, 3x3) to combine and factor the expression as:
#(12x - 3)(x - 3)#
#3(4x-1)(x-3)# Explanation:
#12x^2 -39x+9# Take out a common factor of
#3# first
#3(4x^2-13x+3)# Find factors of
#4 and 3# whose products ADD to 13.
#(4xx3)+(1xx1) =13#
#3(4x-1)(x-3)#
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