Question
A point at the end of a spinning helicopter blade has a centripetal acceleration of 105.8 m/s/s. if the velocity of the blade at this point is 23 m/s, how long is the helicopter blade?
A point at the end of a spinning helicopter blade has a centripetal acceleration of 105.8 m/s/s. if the velocity of the blade at this point is 23 m/s, how long is the helicopter blade?
Answers
#sf(33.5color(white)(x)m)# Explanation:
The centripetal acceleration is given by:
#sf(a=v^2/r)#
#:.# #sf(r=v/a=23^2/105.8=33.5color(white)(x)m)# Dimension check:
#sf((m^2.s^(-2))/(m.s.s)=m)#
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