## Question

## Answers

well, you just...

## Explanation:

...move the terms on the right to the left, and that gives you a nice quadratic equation to solve.

Subtract 19x from both sides:

#2x^2-19x = -3# ...then add 3 to both sides:

#2x^2-19x+3 = 0# ...starting to look familiar?

If

#ax^2 + bx + c = 0# , then

#x = (-b +- sqrt(b^2-4ac))/(2a)# ...so here, a = 2, b = -19, c = 3

#x = (19 +-sqrt((-19^2)-(4 * 2 * 3)))/(2*2)#

#x = (19 +- sqrt(337))/4# x = 9.339 (rounding) or x = 0.161 (rounding)

GOOD LUCK!

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