Question
Acids and bases
A wastewater is simulated as a solution containing \(10^{-2.7} \mathrm{M} \mathrm{NaHCO}_{3}\) and \(10^{-3} \mathrm{M} \mathrm{NH}_{4} \mathrm{Cl}\)
a. List the dissolved species that you expect to be present in solution.
b. Prepare a log \(C-p H\) diagram for the system, and calculate the \(\mathrm{pH}\) of the solution.
c. In order to remove nitrogen by volatilizing \(\mathrm{NH}_{3}\) gas, \(148 \mathrm{mg} / \mathrm{L}\) Ca(OH) \(_{2}\) (lime) will be added to raise the \(\mathrm{pH}\) and convert \(\mathrm{NH}_{4}^{+}\) to the \(\mathrm{NH}_{3}(a q)\) form. Calculate the \(\mathrm{pH}\) after lime addition. (Assume that no \(\mathrm{CaCO}_{3}\) precipitation or ammonia loss takes place during lime addition.)
\(d\). If \(\mathrm{CaCO}_{3}\) precipitation did occur during lime addition, would it raise, lower, or not change the \(\mathrm{pH}\) of the solution? (Hint: Consider what species are removed from solution by this reaction, and what the response would be of the species that remain.)
e. Would removal of \(\mathrm{NH}_{3}(a q)\) by volatilization raise, lower, or not change the \(\mathrm{pH}\) of the solution? Explain your reasoning briefly.
Answers
Wastewater comprises of 10-2.7 M NaHCO3 and 10-3 M NH4Cl
NaHCO3 + NH4Cl -------> NaCl + NH3 + CO2 + H2O
Log C-pH diagram:
10-2.7 M NaHCO3
[Na+] [HCO3-] = 10-2.7
NaHCO3 ------->Na+ + HCO3-
The possible reaction can be:
H2CO3 ------> H+ + HCO3-
HCO3- -------> H+ + CO32-
H2O -------> H+ + OH-
pH = [Na+] [HCO3-] / NaHCO3
pH = - log [OH-]
= - log [10-2.7] = 2.7
Equilibrium Constants can be expresed as:
K1 (of eq 1) = [H+] x [HCO3-]/ [H2CO3]
= 4.3 x 10-7
K2 (of eq 2) = [H+] x [CO32-]/ [HCO3-]
= 5.6 x 10-11
10-3 M NH4Cl
[NH3+] [HCl-] = 10-3
HCl -----> H+ + Cl-
NH4 -------> NH3 + H+
NH3 --------> NH4+ + OH-
pH = [NH3+] [HCl-] / NH4Cl
pH = log [10-3]
= -3
In a Log C-pH diagram, log C is plotted on the X-axis and Y-axis holds the pH value
Now, -pH = log [H+] and log [OH-] = pH - pKw
CT = [NH3+] [NaCl-]
and the graph can be plotted according to the values provided above.
b) NaHCO3 + NH4Cl -------> NaCl + NH3 + CO2 + H2O
In NH4Cl, ammonia (NH3) is a weak base and the strong acid is HCl
In NaHCO3, NaOH acts as a strong base and H2CO3 is a weak acid
NH4Cl is a dominant species