Question
Consider a room of 15m x 15m x 5 m. If the pressure in the room...
consider a room of 15m x 15m x 5 m. If the pressure in the room is 101 kPa and the temperature is 35°C, what is the mass of the air in the room?
Answers
Given data ,
Pressure , P = 101 KPa
Temperature , T = 35 C = 35 +273 = 308 K
Volume , V = 15*15*5 = 1125 m^3
We know from gas equation ,
PV = m R T
m = PV/ RT
m= (101 * 1125 ) / (0.287 * 308 ) [ for air , gas conscent ,R = 0.287 KJ/Kg K ]
m = 1285.40 Kg
Hence mass of the air in the room is 1285.40 Kg
Similar Solved Questions
1 answers
S e s national is considering a olne The try to g et r id or...
s e s national is considering a olne The try to g et r id or productos de ons based on with and without the new products out the co very excited ab company's CFO, has provided the following We New Prats $11, 0 00 37, 14000 rage Botas $5.824.00 um (a) Compute the company return on p rofit magand ...
1 answers
Polyethylene phthalate is a copolymer containing phthalic acid and ethylene glycol. Modify the molecules to show...
Polyethylene phthalate is a copolymer containing phthalic acid and ethylene glycol. Modify the molecules to show the product formed from the condensation of one molecule of 1,2-ethanediol (ethylene glycol) and one molecule of phthalic acid. Select Draw Rings More Erase = atoutus carmens privacy poll...
1 answers
How do you calculate the partial pressure of ammonia in the container after the reaction has reached completion? How do you calculate the volume of the container after the reaction has reached completion?
Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia gas (NH3). You have nitrogen and hydrogen gases in a 15.0 L container fitted with a movable piston (the piston allows the container volume to change so as to keep the pressure constant inside the container). Initially the partial pressu...
1 answers
What are the reagents for these reactions? n. reagent(s); OH VOAc reagent(s); Oy OH o r...
what are the reagents for these reactions? n. reagent(s); OH VOAc reagent(s); Oy OH o r reagent(s); reagentes...
1 answers
A borrower takes out a 30-year adjustable rate mortgage loan for $200,000 with monthly payments. The...
A borrower takes out a 30-year adjustable rate mortgage loan for $200,000 with monthly payments. The first two years of the loan have a “teaser” rate of 4%, after that, the rate can reset with a 2% annual rate cap. On the reset date, the composite rate is 5%. What would the Year 3 monthl...
1 answers
Please answer the following Microbiology question. Which of the following statements is FALSE? A. The activity...
please answer the following Microbiology question. Which of the following statements is FALSE? A. The activity of GTPases is regulated by the association of GTP or GDP with the protein B. Proteolytic cleavage of proteins can activate their activity ° C. Phosphorylation by kinases is an irrev...
1 answers
O Description 3. DETAILS SCALCCC4 3.4.052. If h(x) = V5 + 4f(x), where f(4) = 5...
O Description 3. DETAILS SCALCCC4 3.4.052. If h(x) = V5 + 4f(x), where f(4) = 5 and f '(4) = 3, find h'(4). h'(4) Submit Answer View Previous Question...
1 answers
- 0.863 (Round to three decimal places as needed.) (d) Find the critical t-value that corresponds...
- 0.863 (Round to three decimal places as needed.) (d) Find the critical t-value that corresponds to 99% confidence. Assume 8 degrees of freed I'Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. Il parts showing Clear All...
1 answers
What is missing from my multistep income sheet Aules (@CH H 5 ACC 2001 Project Excel...
what is missing from my multistep income sheet Aules (@CH H 5 ACC 2001 Project Excel File (2) Excel Brittany Konkle File Home Insert Draw Page Layout Formulas Data Review View Help Search Share F32 X f A с D E F G H J J к к 1 L м M N P B S 1 1 2 3 3 B Dress Right Clothing Ad...
1 answers
12 Limiting reactant in salt mixture (write complete formula) Excess reactant in salt mixture (wr...
12 Limiting reactant in salt mixture (write complete formula) Excess reactant in salt mixture (write complete formula) Analysis Moles of CCOrHO(orCC04) precipitated (mol) 0.0024 naal- 00021 Moles of CaC,o, HO (or CaC,0,) precipitated (mol) Moles of limiting reactant in salt mixture (mol) . formula o...
1 answers
MR Demand 10 20 30 40 50 60 70 80 Duantity Refer to Figure 15-20. The...
MR Demand 10 20 30 40 50 60 70 80 Duantity Refer to Figure 15-20. The deadweight loss caused by a profit-maximizing monopoly amounts to a. $900. b. $225. c. $1,350. d. $450 Price MC 4+ F + 1 + 2 + 4 Demand 10 11 12 3 5 6 7 8 9 Quantity Refer to Figure 15-11. Which area represents the deadweight loss...
1 answers
Part A and B (14%) Problem 3: An object is located a distance d .-5.1 cm...
Part A and B (14%) Problem 3: An object is located a distance d .-5.1 cm in front of a concave mirror with a radius of curvature r: 20.9 cm 33% Part (a) Write an expression for the image distance, di Potential 100% (DI 7 | 8 | 9 % per attempt) 0 Hint 2 d, in 33% Part (c) Is this a real or virtua...
1 answers
• Determination of the Dissociation Constant of a Weak Acid Report Sheet The pH at one-half the equivalence point...
• Determination of the Dissociation Constant of a Weak Acid Report Sheet The pH at one-half the equivalence point in an acid-base titration was found to be 5.67. What is the value of K, for this unknown acid? 8. If 30.15 mL of 0.0995 M NaOH is required to neutralize 0.279 g of an unknown acid, ...
1 answers
We have a dataset with n = 10 pairs of observations (Li, Yi), and n X;...
We have a dataset with n = 10 pairs of observations (Li, Yi), and n X; = 683, Yi = 813, i=1 i=1 2* = 47, 405, XiYi = 56,089, Cy? = 66, 731. i=1 i=1 i=1 What is the coefficient of correlation for this data? We have a dataset with n = 10 pairs of observations (li, Yi), and di = 683, Yi = 813, n x* = 4...
1 answers
(4) Find the implicit particular solution of the initial-value problem (e+4y)dx+ (3y +4r)dy 0, y(0) =...
(4) Find the implicit particular solution of the initial-value problem (e+4y)dx+ (3y +4r)dy 0, y(0) = 1 by using the method from Section 2.4....