A 20kN load was hung by a triangular truss as shown below. The member AB and...

Answer: diameter of solid bar d= 25mm 3000 Aso 0 = tan-'(-3000) 0 = 36.87 20 KN tano-3 sinou 3 , Cosos ♡ Joint A: whese FAB FAB FACA Internal force in solid bar AB Internal force in solid bar AC - - - Equelibrium in y-direction: ZOKN => - {fy=0 FACsino - 20 - O FAB = 20 Faces - - en KM $ Tension ? FAB = 100km 3 Equlibrium in x-direction: FAC + FPBcOSO = 0 FACE - FAB woso V

=> Face - 100x - - BORN 3 FAC=- 80 ş Negative sign indicates FAC will be . compressive in nature FACE got x compression ? Stress developed in solid bar AB GABE / FAO 3* TI * 252 = 67.9 Mmm? | SAB= 67.9 N/mm2 { Tension}) Pensile stress developed in soled bar AB > 56 N/mm2 and nearly to 20 N/mm2 So, choose material of sold bar AB 102 Stress developed in solid bar AC GAC= _FAC - Area - 80 x 100 = 54.3 M/mm2 1. 32. 1 x 25?. JAC=54.3 N/mm2 { compression}]

> SON/mm2 and Compressive stress developed in solid bar ac nearly to 56 N/mm2 So choose material of solid bar ACT 102 Answer: A for 102 AB so led bar An, sold bar and AC for Material