## Question

###### How do you solve #38+5x >7 (x+4)#?

How do you solve #38+5x >7 (x+4)#?

## Answers

#x<5# ## Explanation:

#38+5x>7x+28#

#5x-7x> -38+28#

#-2x> -10#

#2x<10#

#x<5#

#x<5# ## Explanation:

First, let's switch the sides:

#7(x+4)<5x+38# Next, we can distribute the

#7# on the left to get

#7x+28<5x+38# Next, subtract

#5x# from both sides to get

#2x+28<38# We can subtract

#28# from both sides to get

#2x<10# Lastly, we divide both sides by

#2# to get

#x<5# Hope this helps!

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