Question
How do you solve #38+5x >7 (x+4)#?
How do you solve #38+5x >7 (x+4)#?
Answers
#x<5# Explanation:
#38+5x>7x+28#
#5x-7x> -38+28#
#-2x> -10#
#2x<10#
#x<5#
#x<5# Explanation:
First, let's switch the sides:
#7(x+4)<5x+38# Next, we can distribute the
#7# on the left to get
#7x+28<5x+38# Next, subtract
#5x# from both sides to get
#2x+28<38# We can subtract
#28# from both sides to get
#2x<10# Lastly, we divide both sides by
#2# to get
#x<5# Hope this helps!
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