## Question

###### E. Yes f) No 6 Exp 9 Calorimetry and Hess's Law Determine the quantity of ice...

e. Yes f) No 6 Exp 9 Calorimetry and Hess's Law Determine the quantity of ice required to absorb exactly 50 kJ of energy when the ice warms from -50.0°C to -10.0°C (specific heat of ice 2.06 J g oc).

## Answers

quantity of heat absorbed = mass of ice x specific heat of ice x ( rise in temperature)

50 x1000 J = mass x 2.06J/g.C x [ (-10) - (-50)]C

thus mass = 50x1000J / 2.06 J/g.C x 40C

=606.79 g

We need 606.79g of ice to absorb 50kJ of heat to bring the temperature from -50 to -10C

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