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What is the sum of #(3b)/(b+2)# and #(12)/(b+2)# in simplest form?

Question

What is the sum of #(3b)/(b+2)# and #(12)/(b+2)# in simplest form?
What is the sum of #(3b)/(b+2)# and #(12)/(b+2)# in simplest form?

Answers

#(3b+12)/(b+2)#

Explanation:

Since the fractions have a common denominator we can add the numerators together.

#rArr(3b)/(b+2)+12/(b+2)=(3b+12)/(b+2)#


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