Question
How do you write an equation of a line going through (3,-1) perpendicular to y=4x+1?
How do you write an equation of a line going through (3,-1) perpendicular to y=4x+1?
Answers
#x+4y+1=0# Explanation:
gradient of the line
#y=4x+1# is#4# Perpendicular means that the gradient of the line perpendicular to the line
#y=4x+1# is#-1/4# because the product of the two gradients must equal to#-1# ie#m_1m_2=-1# Using point gradient formula,
#(y+1)=-1/4(x-3)#
#4y+4=-x+3#
#x+4y+1=0#
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